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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 
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103 年高中高職特色招生考試 數學科計算題
Jan 11th 2014, 03:41

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因為M為 BC中點 所以 CM = BC / 2 因為 AE 平行於 DM 故 CD : AC = CM : CE 所以 CD*CE = AC*CM = AC*BC/2 Δ CDE面積 : ΔABC 面積 = (1/2)CD*CE*sinC : (1/2)AC*BC*sinC = CD*CE : AC*BC = AC*BC/2 :AC*BC = (1/2) : 1 = 1 : 2 故得證...
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